Archonsod said:
Mirathei said:
Yes, and its harder to knock 150 lbs of man +50 lbs of armor out of the saddle than just 150 lbs of man, so Tankai is correct.
No it isn't, by that logic a 150lbs man is more likely to fall over than a 50lb man, which is patently absurd
Unless they have gravity singularities contained in the horseshoes, or else the majority of his weight is contained in his skull.
Not at all what I said. Look, just take into account the most basic laws of physics: assuming the lance hits, the collision will be a textbook inelastic collision, due to this factor:
Archonsod said:
... You'd only run the risk of falling off the horse if the lance failed to penetrate. ... I'd think it'd only be a problem if the lance tip was blunt for some reason.
Assuming that by "failed to penetrate" you allow such situations as the lance entering the victim but not exiting, for whatever reason, then this is quite correct. Now say the victim weighs Y kilograms and is standing still and the cavalryman plus his horse weigh Z kilos plus X kilos of armor for horse and man and are moving at V meters per second towards the victim. Thus:
Total momentum initial=total momentum final=(Z+X)*V=(X+Y+Z)*V'=P
Change in speed for the horse and rider=|V'-V|=dV
Obviously, the more abrupt the change in speed, the harder a time the rider will have staying in the saddle, so to measure how relatively difficult it is, we find the change in speed.
P=(Z+X)*V=(X+Y+Z)*V'
V'=((Z+X)*V)/(X+Y+Z)
dV=|V'-V|
dV=|((Z+X)*V)/(X+Y+Z)-V|
dV=|((Z+X)/(X+Y+Z)-1)*V|
As X increases, (Z+X)/(X+Y+Z) approaches 1, and therefore by the above equation dV approaches 0. Thus as the weight of armor increases, the change in speed the rider undergoes approaches 0. With less change in speed, there is less difficulty withstanding that change in speed. The change in speed is less when the armor is more. Therefore when there is more armor, there is less difficulty resisting the change in speed, as the rider is doing less of it.
Of course, there's two things that make this change, while it does occur, rather insignificant: firstly, the weight of the armor is quite small compared to the weight of the horse and man and thus not significant, and secondly, even if it were enough armor to noticeably reduce the change in speed, the strength of the lancer's arm would then become the limiting factor, if it hadn't been before. He'll probably just drop the lance if he hits something hard enough to jerk him out of the saddle.
Archonsod said:
Besides which, still doesn't affect how hard the lance hits.
Well, actually it does, albeit on a rather insignificant level. I'll use the same physical law again as above, just this time from the victim's perspective. Since the victim's initial velocity is zero, the change for him is simply V'. Using an intermediate step from above, we know the following:
V'=((Z+X)*V)/(X+Y+Z)
V'=((Z+X)/(X+Y+Z))*V
(Z+X)/(X+Y+Z) will always be less than 1, hence why V' is guaranteed to be less than V. However, as X increases, the fraction approaches 1 from below. Thus the greater the weight of the armor, the closer to the horse's galloping speed the victims final velocity will be, thus the greater the jolt he receives. Once again, however, while this difference does exist, it is insignificant, due to the relative lightness of the armor compared to horse and rider and due to the limiting factor of the rider's arm. Also, since the blow is most likely going to kill the victim anyway, it doesn't much matter if it comes with marginally more impact from heavy cavalry.
In short, a cavalryman wearing heavy armor would receive a marginally smaller jolt and deal a slightly harder blow than his lighter counterpart in the event that his lance did not fully skewer the enemy, but the difference is small enough as to be negligible.
Another thing- with such large forces as would make this come into play, not only is the victim almost guaranteed to die regardless, but there is also some small chance that the lance will break, thus changing the entire scenario from a physics perspective.