last game you lucked out pretty hard. That system only works if you exactly don't pick any villains, which as you said is a pretty small chance.HULKSMASH 说:Well, there is about a 20% chance of randomly picking three innocents for mission 1.
Secondly, the part about not knowing if one is a spy is what I covered in my argument at length. Basically, even if we can't know if there's a spy or not, it's still better to renominate the team, because picking a new team has a much higher probability of failure.
Anyways, that's neither here nor there and we can cross that bridge when we get there. Let's hear who everyone wants on the team.
Part of me posting a lot of crap here is that nothing is really going on in the other game. And that is also the reason why I haven't read up the first Resistance game - I've been busy with the WW games. Part of me also probably enjoys being the new kid on the block for once, so I don't blame you for getting that impression. It's been a long time since people didn't expect me to be insightful right off the bat.Eternal 说:I have little analysis on players so far. I'm suspicious of Adaham - he's really playing the "look at me I'm new!" card. Not buying it. I'd assume the guy would at least read parts of the last game, making a lot of his questions this game shockingly stupidly obvious.
Playing the game by chances will not really cut it. + I agree with Amontadillo.Eternal 说:Quickly, allow me to do some maths.
There are 4 spies. There are 6 resistance members. The chance of, on the first mission, getting three straight resistance members?
Easy multiplication. 6/10 * 6/10 * 6/10 = 21.6%.
I have already explained why it would be stupid for the humans to deliberately fail to sabotage the first mission. As such, we're going to run on the assumption that the 3 members are Resistance members.
Your new chances are 3/10. Why 3? Because you removed 3 resistance members from the pool. Whether this is 3/7 or 3/10 I don't actually know (since you technically removed 3 from the pool), but both are lower than 6/10. Let's run the math for both.
.42 * .42 * .42 = 7.4%
3/10 * 3/10 * 3/10 = 2.7%.
Your math is wrong, you are wrong and you are suspicious. HULK is right.
That is true, which reminds me I should ask Austropaio to send a prod to Hawk, who hasn't been active in days. That'd be something if you replaced himNipplemelterina 说:Also, screw your WW game, imma post all I want in it! At least I'm more active than a few other players in it.![]()
I'll see if I can find some time to go through it, might be helpful after all. Since things have been quiet on the WW front, I might use the time before the next ****storm happens.Amontadillo 说:The game isn'T really about calculating percentages, and the other Resistance game is really quick and easy to read through quickly, Ada.
Amontadillo 说:To clarify, nobody actually said the odds of picking an all resistance team were better when picking a new team, unless I've missed something.
What has been said is that it's impossible to know whether the first team are actually all mutants, and that it's better to pick a new team to gain more information on everybody, and that it's not that likely to pick an all resistance team in the first place.
Nipplemelterina 说:Why would it be dumb for a spy to not sabotage the first mission? True, it would make it harder for them to win, but similar to voting for a wolf as a wolf in WW, can't it also be a way of gaining trust that can be used to create confusion later in the game and to cause those missions to fail?
Adaham 说:In other news, I'm terrible at math, meaning my head starts spinning at the moment you wrote 21.6%. If this game is going to be mostly about calculating percentages, I will probably not be much of an asset.
With sentences like these, you should go into politics.Eternal 说:I don't buy into vague terms. I buy into win percentages.
I know you didn't accuse me based on your stats and I didn't claim so. By putting these two together in one sentence you're making it look like I defended myself by attacking your math. Not only are you misrepresenting my defense, you are also ignoring the part in which I addressed your accusations of "bull**** newbishness". Whether you believe me or not is another thing.A lot of people don't like math and aren't good at it. For me, if I can rely on cold numbers that are true or on random "gut instincts" or the ways that people refer to other players, I will. However, both elements most definitely play a very important role, and I accused you based on your bull**** newbishness and not on my statistics of you being a spy.
As I said, I'll have a read through it, probably I'll start later when I'm walking the dog.The other game should be evidence for why you should rely on stats. You had an all-resistance team, you re-used it, and you re-used it again and sure enough you won. Let's keep that idea in mind.
Amontadillo 说:Doesn'T actually answer why you accused all of us of having wrong maths and being suspicious when nobody actually made that claim.
Amontadillo 说:Also, you're ignoring the part where there's NO WAY TO TELL whether you got an all resistance team.
Eternal 说:1) If you can get a huge leap ahead, you take it. You're taking a pretty big risk by not sabotaging, especially when 3 successful sabotages (right?) wins you the game. In Werewolf, you have quite a few day/night cycles where it's worth it to be innocent all along. Here, it's three.
2) As I've mentioned above, you gain actually little information from a failed mission. One of the three is a saboteur, and that's all you know.
There is ALWAYS a chance that a saboteur on the first mission won't sabotage, or the possibility that there's two saboteurs on it and they both sabotaged or neither did or whatever. However, these percentages are rather miniscule and even when they aren't they don't play a particularly large role in the outcome.
Amontadillo 说:since Eternal is so fond of math perhaps he could work out the liklihood of any one of those being a bad guy, hmmmm?![]()
Xardob 说:Ok, first things first, Eternal sucks at math. It's not a simple (6/10)^3. It's 6/10 * 5/9 * 4/8, which gives us 16,7% chance of randomly selecting an all resistance team.
By putting these two together in one sentence you're making it look like I defended myself by attacking your math. Not only are you misrepresenting my defense, you are also ignoring the part in which I addressed your accusations of "bull**** newbishness". Whether you believe me or not is another thing.
Adaham 说:Right now I don't have so much a problem with your math, as rather with how you're accusing me of playing dumb. On the last two pages I made some serious posts which even Ninja'd similar posts of Amontadillo and Nipple. I don't need a medal for that, but I think I'm getting the hang of this rather fast. It's not entirely honest of you to paint me like I'm playing the noob-card.
Still wrong. It should be 3/7 * 2/6 * 1/5, which is 2,8%.Eternal 说:As embarrassing as this is, this calls for an update to my other maths too.
Swapping out an all-Resistance team for another team? 3/7 * 2/7 * 1/7. That's 1.7% of having a second all-Resistance team, and thus succeeding in the mission.
The only scenario we should consider completely ignoring the first mission team is if there's more than one Spy in the team. If there's only one, it's still statistically better to keep some of them around.tl;dr if you succeed in first mission keep the team.
I was wondering if you would suggest this again. I'm not sure if this gives us that much information, but it isn't a worse choice than any other, right now.HULKSMASH 说:I wish grimmend would check in, I think it may be good to have him on the mission team, as he is spearheading the second mission, and it would be good to get a read on him before he starts proposing a team.