Post a riddle!

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Doesn't have to be equilateral. The medians of any triangle are all concurrent, at a point called the centroid. As long as there's a tree at each vertex and a tree at each midpoint of the three sides, the final tree can be placed on the centroid and it will work.
 
or you can take any triangle, and then any random point inside it, then join each vertex to the inner point and extend those segments until they intersect the triangle and use the intersections along with the other 4 points
 
Varalir 说:
Was it obvious?  :razz:


I'll try the tree one.


    .
  . . .
  .  .  .  This right? Your hint might've been more than a hint then  :razz:


New riddle: It makes a loud sound and walks a hard path all it's life. It kisses with two mouths and only in heat. What is it?

Good is thy riddle, Varalir,
    and guessed it is:
that is the goldsmith’s hammer with which gold is beaten.

Guess this riddle, since wise thou seemest,
  what said Óthin in Baldr’s ear
    before he was borne to the fire?
 
arteofwar 说:
Guess this riddle, since wise thou seemest,
  what said Óthin in Baldr’s ear
    before he was borne to the fire?
Lo and doth Óthin say
    In Baldr`s ear
          benis
 
because why not
picture a pyramid with n layers of cells with numbers
the first layer has 1 cell with a number (Let it be zero, its value isn't important)
each subsequent layer has 1 more cell  (the numbers in these can be any whole positive number)
the last layer has n cells, of course.
now imagine you are at the top layer and you want to get to the bottom layer.
rules are: you can only go down (not from the second layer to the first layer again etc), and you can only go to one of the two immediate number cells under you.
as you go down you add up the value of each cell you pass through.
question is: how to determine the best path? i.e which path gives you the biggest sum?
the pyramid might look like this:
pyramid-solution1.gif


for example: the pyramid
1
3 5​
obviously the best path is 1->5. totaling 6

the pyramid
0
1 0
1 0 6​
here  one would go 0_0_6 , 6 in total.
of course we can try all the paths and compare them , but this becomes stupidly hard as the number of layers grow.
the possible amount of paths is 2^(n-1) so a 7 layer pyramid has 64 paths. each of which is composed of n sums. so it is a lot of calculations to do manually
 
No one knows if I get wet or if the water gets me
(The answer is old and maybe if you know physics you'll get it)
 
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