Lord Rich 说:
The team order seems to be a little odd, DoF and AE are paired up every single set and so are Wolfpack and Castellans. It seems strange that some teams would stay paired like that yet others play alongside every other team and aren't locked to another.
As an alternative how about:
This combination ensures each team mixes with 6 of the other teams twice and never mixes with a single other team.
ABCD vs EFGH
ABEF vs CDGH
ACEG vs BDFH
ADFG vs BCEH
This combination ensures every team mixes with every other team at least once and never four times.
ABCD vs EFGH
ABEF vs CDGH
ACEG vs BDFH
AHCF vs BGDE
There was never a siege tournament before with such settings, so we appreciate every suggestions to improve our system. Thx Azan.
I haven't yet randomized the teams that have signed up to the placeholders "Team A, B ...". So it might not be DoF and AE that are always paired. But you are right, one team is always paired with one other team and 2 teams will be always opponents in the current solution.
I like the idea you suggested, but there is one condition that isn't taken into account. I searched for a solution in which the teams start equally in the first round on each map as defenders or attackers. Cause I think it might be a difference if you always start as defender first on each (new) map. If you take this condition into account, you would need to have at least 14 rounds (2 on each map) to fully counter balance all teams.
Sadly, we have only 8 rounds and so far I know there is no chance to get this problem fixed with 8 rounds.
But if the admins and (most) of the participating teams agree that we can ignore the positioning (attacker vs. defender) in the first round on each map, I am up for using your second suggestion:
ABCD vs EFGH
ABEF vs CDGH
ACEG vs BDFH
AHCF vs BGDE
Although Team A will always start as defender in the first round of each map.
Alright, what do the participating teams think? Is it a greater disadvantage 'not to be paired with every team during the tournament' or 'to start as a defender on each (new) map'?
Edit:
Lord Rich 说:
Additionally it means that the only difference between the final scores for the paired teams comes out of kills.
This is a strong argument for your solution and you finally convinced me that the equal positioning might be a less significant condition. So I tend to prefer your solution.